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A triangle has sides of length (n^2+n+1), (2n+1) and (n^2-1) where n>1.
Explain why the side (n^2+n+1) must be the longest side of the triangle ( 3 MARKS)
Please show the solution.
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(n^2+n+1)>n^2-1 this inequality is true for any integer n>1
(n^2+n+1)>2n+1 this inequality is true for any integer n>1
So, the side n^2+n+1 is the greatest side
Hope this help!
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