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by **Lucas** » Sun Mar 10, 2013 8:59 am

MYP Maths, Coordinate geometry, Distance between two points

How can we find the parameter c if these A(1,c) and B(-3,4) are 5 units apart?

Thanks

by **miranda** » Sun Mar 10, 2013 9:28 am

MYP Math, Distance between two points, Distance Formula

The distance between two points $A(x_{1}, y_{1})$ and $B(x_{2}, y_{2})$ is given by the following formula:
$d_{AB}= \sqrt{( x_{2}- x_{1})^2+( y_{2}- y_{1})^2}$

Applying the above formula in our case we have

$d_{AB}= \sqrt{( -3- 1)^2+( 4- c)^2}=\sqrt{16+( 4- c)^2}=5 =>$

$=>( \sqrt{16+( 4- c)^2})^2=5^2 =>$ (by squaring both sides)

$=>(16+(4- c)^2) =25 => (4- c)^2 = 9=> (4- c) =\pm 3 =>$

$c=1 \or\ c=7$

Hope these help! :lol:

by **Lucas** » Sat Apr 06, 2013 7:49 pm

thanks miranda!!

by **Lucas** » Sat Apr 06, 2013 7:50 pm

thanks miranda!!

by **Lucas** » Sat Apr 06, 2013 7:52 pm

thanks miranda!!

by **Lucas** » Sat Apr 06, 2013 7:52 pm

thanks miranda!!

by **Lucas** » Sat Apr 06, 2013 7:53 pm

thanks miranda!!

by **Lucas** » Sat Apr 06, 2013 7:54 pm

thanks miranda!!

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MYP Mathematics, Distance between two points

MYP Mathematics, Distance between two points

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