IB Mathematical Studies SL – Calculus, Derivatives, Differentiation, Equation of TangentWe know that the gradient of a curve
)
at any point
)
is equal to the gradient of the tangent (

) to the curve at that point.
So about your question we have that
=6x-5)
and the gradient of the tangent (

) at the point
)
is
=6-5=1)
and the equation of the tangent is given by the following formula
(x-x_{0}))
where in your case
=(1,-2))
and finally the equation of the tangent is
=1(x-1) \Rightarrow y=x-3)
Hope these help!!