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by **Nyla** » Tue Jan 21, 2014 7:18 pm

[color=#004040]Inequalities with Absolute value – IB math SL[/color]

How can we find the set of values of x for which

$|2x-1|<|x+3|$ ?

Thanks!

by **miranda** » Tue Jan 21, 2014 7:20 pm

Solving Inequalities with Absolute value – IB math SL

$|x-1|<|x-4| \Rightarrow |x-1|^2<|x-4|^2$

$(x-1)^2<(x-4)^2 \Rightarrow x^2-2x+1<x^2-8x+16$

$6x<15 \Rightarrow x<\frac{15}{6}$

Hope these help!

by **Nyla** » Tue Jan 21, 2014 7:20 pm

Thank you!

ib maths4u | ib maths | ib math | ib mathematics

Inequalities with Absolute value – IB maths SL

Inequalities with Absolute value – IB maths SL

Re: Inequalities with Absolute value – IB maths SL

Re: Inequalities with Absolute value – IB mats SL