## IB Maths SL Vectors, Lines parametric form

Algebra, Functions and equations, Circular functions and trigonometry, Vectors, Statistics and probability, Calculus. IB Maths SL Revision Notes

### IB Maths SL Vectors, Lines parametric form

IB Mathematics SL – Vectors, parametric form of a line

How can we find the parametric form of the equations of the line passing through the point (2,7) and is parallel to the vector $b= \begin{pmatrix} 6 \\ -4 \end{pmatrix}$ ?

Thanks
Jack

Posts: 0
Joined: Mon Jan 28, 2013 8:08 pm

### Re: IB Maths SL Vectors, Lines parametric form

IB Mathematics HL – Vectors, parametric form

The Parametric form for the equation of a straight line is :

$x=a_{1} + \lambda b_{1}$

$y=a_{2} + \lambda b_{2}$

where $a= \begin{pmatrix} a_{1} \\ a_{2} \end{pmatrix}$ is a position vector (a point on the line)

and $b= \begin{pmatrix} b_{1} \\ b_{2} \end{pmatrix}$ is a direction vector ( a vector parallel to the line)

$\lambda$ is a real number parameter.

Therefore about your question we have that the parametric equation form is

$x=2 +6\lambda$

$y=7 -4 \lambda$

Hope these help!
miranda

Posts: 268
Joined: Mon Jan 28, 2013 8:03 pm