## IB Maths SL Vectors, Lines

Algebra, Functions and equations, Circular functions and trigonometry, Vectors, Statistics and probability, Calculus. IB Maths SL Revision Notes

### IB Maths SL Vectors, Lines

IB Mathematics SL – Vectors, Vector equation of a line

How can we find the vector equation of the line passing through the point (2,7) and is parallel to the vector $b= \begin{pmatrix} 6 \\ -4 \end{pmatrix}$ ?

Thanks
Jack

Posts: 0
Joined: Mon Jan 28, 2013 8:08 pm

### Re: IB Maths SL Vectors, Lines

IB Mathematics SL – Vectors, Vector equation of a line

The vector equation of a line is given by the following formula

$r=a+ \lambda b$

where a is a position vector of the line (i.e. a point on the line) , b is a direction vector (i.e. a vector parallel to the line) and $\lambda$ is a real number parameter.
So the vector equation of the line is given by the formula

$r= \begin{pmatrix} 2 \\ 7 \end{pmatrix}+ \lambda \begin{pmatrix} 6 \\ -4 \end{pmatrix}$

Hope these help!
miranda

Posts: 268
Joined: Mon Jan 28, 2013 8:03 pm